Same chapter3 marksDifficulty: Medium
What is an abstract class, and how does it differ from an interface in Java?
Inheritance and Polymorphism
3 marksDifficulty: Medium
A class B extends class A, and both define a method show(). If A a = new B(); a.show(); is executed, which version runs and why?
Original Khojo Papers practice question — not from a past board paper.
Answer
The version defined in B runs, because an overridden method is resolved at run time by the actual type of the object, which is B.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Explanation
If show() were static instead, the version in A would run, because static methods are bound at compile time.
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