For a first-order reaction, 50% of the reactant is used up in 10 minutes. What fraction remains after 30 minutes?
Chemical Kinetics
Original Khojo Papers practice question — not from a past board paper.
About 0.0347 min−1
No citable source has been recorded for this record. Treat it as practice material, not as fact.
For a first-order reaction t½ = 0.693/k, so k = 0.693 ÷ 20 = 0.0347 min−1.
From the same topic and chapter, at a similar level.
For a first-order reaction, 50% of the reactant is used up in 10 minutes. What fraction remains after 30 minutes?
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Solutions