Find the equation of the plane passing through (1, 2, 3) with normal vector 2i − j + 3k.
Three-Dimensional Geometry
Original Khojo Papers practice question — not from a past board paper.
cos−1(4/21), about 79°
No citable source has been recorded for this record. Treat it as practice material, not as fact.
The angle between two planes is the angle between their normals, so cos θ = (6 − 6 + 4) ÷ (3 × 7) = 4/21.
From the same topic and chapter, at a similar level.
Find the equation of the plane passing through (1, 2, 3) with normal vector 2i − j + 3k.
Three-Dimensional Geometry
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