Find the area of the triangle with vertices (1, 2), (4, 6) and (−2, 3) using determinants.
Determinants
Original Khojo Papers practice question — not from a past board paper.
The determinant of [[1, 2, 1], [3, 6, 1], [5, 10, 1]] is zero, so the area of the triangle is zero and the points are collinear.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Expanding gives 1(6 − 10) − 2(3 − 5) + 1(30 − 30) = −4 + 4 + 0 = 0.
From the same topic and chapter, at a similar level.
Find the area of the triangle with vertices (1, 2), (4, 6) and (−2, 3) using determinants.
Determinants
If A is a 3 × 3 matrix with |A| = 5, find |2A| and |adj A|.
Determinants
State the condition on the determinant of the coefficient matrix for a system of linear equations to have a unique solution.
Determinants
Evaluate the determinant of [[1, 2, 3], [4, 5, 6], [7, 8, 9]].
Determinants
If A = [[1, 2], [3, 4]] and B = [[0, 1], [1, 0]], find AB and BA and state whether they are equal.
Matrices
Find the projection of a = 2i + 3j + 2k on b = i + 2j + k.
Vectors