Same chapter3 marksDifficulty: Medium
A body is thrown vertically upwards with a speed of 30 m s−1. Find the maximum height it reaches and the time it takes to return. Take g = 10 m s−2.
Kinematics
3 marksDifficulty: Medium
A body is projected with a speed of 20 m s−1 at 30° to the horizontal. Find the maximum height reached and the time of flight. Take g = 10 m s−2.
Original Khojo Papers practice question — not from a past board paper.
Answer
Maximum height 5 m and time of flight 2 s.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Explanation
The vertical component is 20 sin 30° = 10 m s−1. The maximum height is u2sin2θ/2g = 100/20 = 5 m and the time of flight is 2u sin θ/g = 20/10 = 2 s.
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