Differentiate y = (2x + 1)/(x − 3) with respect to x.
Limits and Derivatives
Original Khojo Papers practice question — not from a past board paper.
1/2
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Using 1 − cos x = 2sin2(x/2), the expression becomes 2sin2(x/2)/x2 = (1/2)[sin(x/2)/(x/2)]2, which tends to 1/2.
From the same topic and chapter, at a similar level.
Differentiate y = (2x + 1)/(x − 3) with respect to x.
Limits and Derivatives
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Limits and Derivatives
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Limits and Derivatives
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Limits and Derivatives