Prove that (sec A − tan A)(sec A + tan A) = 1.
Trigonometric Identities
Original Khojo Papers practice question — not from a past board paper.
Multiplying numerator and denominator by (1 + sin A) gives (1 + sin A)2/cos2A, which is (1/cos A + sin A/cos A)2 = (sec A + tan A)2.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
The step that matters is 1 − sin2A = cos2A in the denominator.
From the same topic and chapter, at a similar level.
Prove that (sec A − tan A)(sec A + tan A) = 1.
Trigonometric Identities
Prove that (1 − cos2θ) cosec2θ = 1.
Trigonometric Identities
If tan θ = 4/3, find the value of (sin θ + cos θ)/(sin θ − cos θ).
Trigonometric Identities
If sin θ = 3/5 and θ is acute, find cos θ and tan θ.
Trigonometric Identities
Prove that tan θ + cot θ = sec θ cosec θ.
Trigonometric Identities
Evaluate (sin2 30° + cos2 45°) ÷ (tan2 60° − cot2 45°).
Trigonometric Identities