In a right-angled triangle, sin θ is:
Trigonometrical Ratios
Original Khojo Papers practice question — not from a past board paper.
For an acute angle θ, sine is the opposite side over the hypotenuse, cosine the adjacent side over the hypotenuse and tangent the opposite over the adjacent. Cosecant, secant and cotangent are the reciprocals of sine, cosine and tangent respectively.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
The ratios depend only on the angle and not on the size of the triangle.
From the same topic and chapter, at a similar level.
In a right-angled triangle, sin θ is:
Trigonometrical Ratios
If sin θ = 3/5, find the value of cos θ, where θ is an acute angle.
Trigonometrical Ratios
If cos θ = 12/13 and θ is acute, find sin θ and cot θ.
Trigonometrical Ratios
If sin A = 5/13 and A is acute, find cos A and tan A.
Trigonometrical Ratios
Prove that sin2θ + cos2θ = 1 for an acute angle θ.
Trigonometrical Ratios
If tan θ = 3/4, find sin θ and cos θ for an acute angle θ.
Trigonometrical Ratios