At what height above the earth's surface does the acceleration due to gravity fall to one-fourth of its surface value? Take R = 6,400 km.
Gravitation
Original Khojo Papers practice question — not from a past board paper.
A geostationary satellite appears fixed above one point on the earth's surface. Its period of revolution must be 24 hours, and it must move in the plane of the equator from west to east, which puts it at a height of about 36,000 km.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Such satellites are used for communication and weather observation.
From the same topic and chapter, at a similar level.
At what height above the earth's surface does the acceleration due to gravity fall to one-fourth of its surface value? Take R = 6,400 km.
Gravitation
A satellite orbits close to the earth's surface. Find its orbital speed. Take g = 9.8 m s−2 and R = 6.4 × 106 m.
Gravitation
Calculate the escape velocity from the surface of the earth, given g = 9.8 m s−2 and R = 6.4 × 106 m.
Gravitation
State Kepler's three laws of planetary motion.
Gravitation
Distinguish between the acceleration due to gravity and the universal gravitational constant.
Gravitation
For a projectile launched at speed u, at what angle is the horizontal range greatest, and what is that range?
Kinematics