Solve for x: log₂ x + log₂ (x − 2) = 3.

x = 4

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Explanation

The equation becomes log₂[x(x − 2)] = 3, so x² − 2x = 8, that is x² − 2x − 8 = 0 and x = 4 or −2. Only x = 4 is admissible, because a logarithm is defined only for a positive number.