Why can a tangent not be constructed from a point inside a circle?
Constructions
Original Khojo Papers practice question — not from a past board paper.
The point is the incentre, found where the bisectors of any two of the angles meet.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
The locus of points equidistant from two sides is the bisector of the angle between them, so the point common to two such bisectors is equidistant from all three sides.
From the same topic and chapter, at a similar level.
Why can a tangent not be constructed from a point inside a circle?
Constructions
Construct a regular hexagon of side 4 cm and draw its circumscribed circle. State the radius of that circle.
Constructions
Construct a triangle ABC with AB = 6 cm, BC = 7 cm and CA = 5 cm, and then construct its circumcircle. State how the centre is found.
Constructions
Construct a circle of radius 4 cm and, from a point 7 cm from its centre, construct the two tangents to the circle. State the length of each tangent.
Constructions
Construct a triangle with sides 5 cm, 6 cm and 7 cm and then construct its incircle. State how the centre and the radius are found.
Constructions
Construct a triangle ABC with BC = 6 cm, angle B = 60° and AB = 5 cm, then construct the perpendicular from A to BC.
Constructions