Calculate the root mean square speed of oxygen molecules at 300 K. Take R = 8.31 J mol−1 K−1 and M = 0.032 kg mol−1.
Behaviour of Perfect Gases and Kinetic Theory of Gases
Original Khojo Papers practice question — not from a past board paper.
The law states that the energy of a system in thermal equilibrium is shared equally among all its degrees of freedom, each contributing ½kT per molecule. A monatomic molecule has three translational degrees of freedom; a diatomic molecule has three translational and two rotational, that is five at ordinary temperatures.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
The ratio of the specific heats follows directly from the number of degrees of freedom.
From the same topic and chapter, at a similar level.
Calculate the root mean square speed of oxygen molecules at 300 K. Take R = 8.31 J mol−1 K−1 and M = 0.032 kg mol−1.
Behaviour of Perfect Gases and Kinetic Theory of Gases
What is mean free path, and on what does it depend?
Behaviour of Perfect Gases and Kinetic Theory of Gases
Calculate the volume occupied by 2 moles of an ideal gas at 300 K and 1 atmosphere. Take R = 8.31 J mol−1 K−1 and 1 atm = 1.013 × 105 Pa.
Behaviour of Perfect Gases and Kinetic Theory of Gases
State the postulates of the kinetic theory of gases.
Behaviour of Perfect Gases and Kinetic Theory of Gases
For a projectile launched at speed u, at what angle is the horizontal range greatest, and what is that range?
Kinematics
How many significant figures are there in 0.00420, 1.030 and 6.023 × 1023?
Physical World and Measurement