Find the equation of the perpendicular bisector of the segment joining (1, 2) and (5, 6).
Equation of a Straight Line
Original Khojo Papers practice question — not from a past board paper.
Both slopes are 1, so the three points are collinear.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Slope of AB = (2 − 5)/(−1 − 2) = 1 and slope of BC = (8 − 2)/(5 + 1) = 1. Two segments with a common point and equal slopes lie on the same line.
From the same topic and chapter, at a similar level.
Find the equation of the perpendicular bisector of the segment joining (1, 2) and (5, 6).
Equation of a Straight Line
Find the equation of the line passing through (0, 4) and (−3, 0).
Equation of a Straight Line
Find the equation of the line through (1, 2) with slope 3.
Equation of a Straight Line
Find the slope of the line passing through (2, 3) and (4, 7).
Equation of a Straight Line
For the line 2x + 3y = 6, find the slope, the x-intercept and the y-intercept.
Equation of a Straight Line
Find the equation of the line through (3, −2) that is parallel to 4x − 3y = 5.
Equation of a Straight Line