Same chapter3 marksDifficulty: Medium
Describe the Hoffmann bromamide degradation and state what it achieves.
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3 marksDifficulty: Medium
Arrange aniline, methylamine, dimethylamine and ammonia in order of increasing basicity in aqueous solution.
Original Khojo Papers practice question — not from a past board paper.
Answer
Aniline < ammonia < methylamine < dimethylamine. The alkyl groups release electrons and make the lone pair more available, while in aniline the lone pair is delocalised into the ring and is least available.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Explanation
Trimethylamine is a weaker base than dimethylamine in water because of steric hindrance to solvation of its conjugate acid.
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