Original Khojo Papers practice question — not from a past board paper.
28 g
No citable source has been recorded for this record. Treat it as practice material, not as fact.
CaCO3 → CaO + CO2. The relative molecular masses are 100 and 56, so 100 g of calcium carbonate gives 56 g of calcium oxide. Therefore 50 g gives 50 × 56/100 = 28 g.
From the same topic and chapter, at a similar level.
What volume of oxygen at S.T.P. is needed for the complete combustion of 10 dm3 of methane, and what volume of carbon dioxide is formed? All volumes are measured at the same conditions.
Mole Concept and Stoichiometry
When 6 g of magnesium is burnt in oxygen, what mass of magnesium oxide is formed? (Mg = 24, O = 16)
Mole Concept and Stoichiometry
Calculate the mass of calcium oxide obtained by heating 100 g of pure calcium carbonate. (Ca = 40, C = 12, O = 16)
Mole Concept and Stoichiometry
A compound contains 40% carbon, 6.7% hydrogen and 53.3% oxygen by mass. Find its empirical formula. (C = 12, H = 1, O = 16)
Mole Concept and Stoichiometry
Calculate the volume occupied by 0.5 mole of any gas at S.T.P.
Mole Concept and Stoichiometry
Calculate the number of moles in 88 g of carbon dioxide. (C = 12, O = 16)
Mole Concept and Stoichiometry
