Why does a coin at the bottom of a beaker of water appear to be raised?
Refraction of Light at Plane Surfaces
Original Khojo Papers practice question — not from a past board paper.
Light entering the fibre strikes the boundary between the denser core and the rarer cladding at an angle greater than the critical angle, so none of it escapes and all of it is reflected back into the core. This happens repeatedly along the fibre, so the light follows the fibre even where it bends.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Because no light is lost by refraction at the wall, the signal can travel long distances with little loss.
From the same topic and chapter, at a similar level.
Why does a coin at the bottom of a beaker of water appear to be raised?
Refraction of Light at Plane Surfaces
A ray of light travelling in air strikes a glass surface at an angle of incidence of 60°. If the refractive index of glass is 1.5, find the sine of the angle of refraction.
Refraction of Light at Plane Surfaces
The critical angle for a certain medium is 30°. Calculate its refractive index.
Refraction of Light at Plane Surfaces
State the two conditions necessary for total internal reflection to take place.
Refraction of Light at Plane Surfaces
The refractive index of glass is 1.5 and the speed of light in vacuum is 3 × 108 m s−1. Calculate the speed of light in glass.
Refraction of Light at Plane Surfaces
A tank is filled with water to a depth of 40 cm. If the refractive index of water is 4/3, find the apparent depth of the tank.
Refraction of Light at Plane Surfaces