Same chapter3 marksDifficulty: Medium
Calculate the enthalpy change of a reaction whose bond enthalpies give 1,200 kJ absorbed to break bonds and 1,500 kJ released to form them.
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3 marksDifficulty: Medium
State the relation between Gibbs energy, enthalpy and entropy, and the condition for a spontaneous process.
Original Khojo Papers practice question — not from a past board paper.
Answer
ΔG = ΔH − TΔS. A process is spontaneous at constant temperature and pressure when ΔG is negative, at equilibrium when ΔG is zero, and non-spontaneous when ΔG is positive.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Explanation
A reaction with a positive ΔH can still be spontaneous if TΔS is large enough.
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