The midpoint of the segment joining A(2, k) and B(6, 8) is (4, 5). Find k.
Section and Distance Formula
Original Khojo Papers practice question — not from a past board paper.
(3, 5)
No citable source has been recorded for this record. Treat it as practice material, not as fact.
By the section formula the point is ((1×7 + 2×1)/3, (1×11 + 2×2)/3) = (9/3, 15/3) = (3, 5).
From the same topic and chapter, at a similar level.
The midpoint of the segment joining A(2, k) and B(6, 8) is (4, 5). Find k.
Section and Distance Formula
Show that the points (1, 1), (4, 4) and (6, 6) are collinear using the distance formula.
Section and Distance Formula
Find the centroid of the triangle whose vertices are (1, 2), (3, −4) and (5, 8).
Section and Distance Formula
Find the ratio in which the x-axis divides the line segment joining (2, −3) and (5, 6).
Section and Distance Formula
Find k if the distance between (2, −3) and (10, k) is 10 units.
Section and Distance Formula
The midpoint of the segment joining (a, b) and (c, d) is:
Section and Distance Formula