The midpoint of the segment joining A(2, k) and B(6, 8) is (4, 5). Find k.
Section and Distance Formula
Original Khojo Papers practice question — not from a past board paper.
They are collinear because the distance from (1,1) to (4,4) plus the distance from (4,4) to (6,6) equals the distance from (1,1) to (6,6).
No citable source has been recorded for this record. Treat it as practice material, not as fact.
The three distances are 3√2, 2√2 and 5√2, and 3√2 + 2√2 = 5√2, so the middle point lies on the segment joining the other two.
From the same topic and chapter, at a similar level.
The midpoint of the segment joining A(2, k) and B(6, 8) is (4, 5). Find k.
Section and Distance Formula
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Section and Distance Formula
Find the coordinates of the point that divides the join of (1, 2) and (7, 11) internally in the ratio 1 : 2.
Section and Distance Formula
Find the centroid of the triangle whose vertices are (1, 2), (3, −4) and (5, 8).
Section and Distance Formula
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Section and Distance Formula
The midpoint of the segment joining (a, b) and (c, d) is:
Section and Distance Formula