The distance of the point (5, 12) from the origin is:
Section and Distance Formula
Original Khojo Papers practice question — not from a past board paper.
13 units
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Distance = √[(2 − (−3))2 + (−8 − 4)2] = √(25 + 144) = √169 = 13 units.
From the same topic and chapter, at a similar level.
The distance of the point (5, 12) from the origin is:
Section and Distance Formula
Find the midpoint of the segment joining (−2, 5) and (6, −1).
Section and Distance Formula
Find the distance between (3, 4) and (−3, −4).
Section and Distance Formula
Find the distance between the points (2, 3) and (6, 6).
Section and Distance Formula
Find the coordinates of the point that divides the join of (1, 2) and (7, 11) internally in the ratio 1 : 2.
Section and Distance Formula
Find the centroid of the triangle whose vertices are (1, 2), (3, −4) and (5, 8).
Section and Distance Formula