A person cannot see distant objects clearly. Name the defect, the lens used to correct it, and explain why that lens works.
Refraction through a Lens
Original Khojo Papers practice question — not from a past board paper.
The image is 60 cm from the lens on the other side, real, inverted and three times the size of the object.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Using 1/v − 1/u = 1/f with u = −20 cm and f = +15 cm, 1/v = 1/15 − 1/20 = 1/60, so v = +60 cm. The magnification is v/u = 60/(−20) = −3.
From the same topic and chapter, at a similar level.
A person cannot see distant objects clearly. Name the defect, the lens used to correct it, and explain why that lens works.
Refraction through a Lens
State two differences between the image formed by a converging lens and that formed by a diverging lens for a real object.
Refraction through a Lens
Where must an object be placed in front of a converging lens for the image to be virtual, erect and magnified? Name one use of this arrangement.
Refraction through a Lens
Find the power of a converging lens of focal length 25 cm.
Refraction through a Lens
A diverging lens has a focal length of 20 cm. Find its power.
Refraction through a Lens
Draw a ray diagram to show the image formed by a converging lens when the object is placed between the focus and twice the focal length.
Refraction through a Lens