Where must an object be placed in front of a converging lens for the image to be virtual, erect and magnified? Name one use of this arrangement.
Refraction through a Lens
Original Khojo Papers practice question — not from a past board paper.
The image is 30 cm from the lens, 6 cm tall, real and inverted.
No citable source has been recorded for this record. Treat it as practice material, not as fact.
With u = −15 cm and f = +10 cm, 1/v = 1/10 − 1/15 = 1/30, so v = +30 cm. The magnification is 30/(−15) = −2, so the image is inverted and twice as tall, that is 6 cm.
From the same topic and chapter, at a similar level.
Where must an object be placed in front of a converging lens for the image to be virtual, erect and magnified? Name one use of this arrangement.
Refraction through a Lens
A diverging lens has a focal length of 20 cm. Find its power.
Refraction through a Lens
An object is placed 20 cm from a converging lens of focal length 15 cm. Find the position, nature and magnification of the image.
Refraction through a Lens
State two differences between the image formed by a converging lens and that formed by a diverging lens for a real object.
Refraction through a Lens
Find the power of a converging lens of focal length 25 cm.
Refraction through a Lens
A person cannot see distant objects clearly. Name the defect, the lens used to correct it, and explain why that lens works.
Refraction through a Lens