Why is water used as a coolant in car radiators and in industrial cooling?
Calorimetry
Original Khojo Papers practice question — not from a past board paper.
23,100 J
No citable source has been recorded for this record. Treat it as practice material, not as fact.
Melting the ice needs 50 × 336 = 16,800 J and warming the water needs 50 × 4.2 × 30 = 6,300 J, so the total is 23,100 J.
From the same topic and chapter, at a similar level.
Why is water used as a coolant in car radiators and in industrial cooling?
Calorimetry
Calculate the heat needed to melt 100 g of ice at 0 °C into water at 0 °C. Take the specific latent heat of fusion of ice as 336 J g−1.
Calorimetry
Define specific heat capacity and state its SI unit.
Calorimetry
Why does the temperature of a substance not change while it is melting, even though heat is being supplied?
Calorimetry
Calculate the heat needed to raise the temperature of 200 g of water from 20 °C to 100 °C. Take the specific heat capacity of water as 4200 J kg−1 K−1.
Calorimetry
Why is a burn caused by steam at 100 °C more severe than one caused by water at 100 °C?
Calorimetry